This Means RaWaR

The Overlord of the Über-Feral says: Welcome to my bijou bloguette. You can scroll down to sample more or simply:

• Read a Writerization at Random: RaWaR

• O.o.t.Ü.-F.: More Maverick than a Monkey-Munching Mingrelian Myrmecologist Marinated in Mescaline…

• ¿And What Doth It Mean To Be Flesh?

მათემატიკა მსოფლიოს მეფე

*Der Muntsch ist Etwas, das überwunden werden soll.


Santa Ana

Biblia anagrammatica, or, The anagrammatic Bible: a literary curiosity gathered from unexplored sources and from books of the greatest rarity, Rev. Walter Begley, Privately Printed for the Author, 1904


After considerable research, I have only discovered two writers who have attempted this excessively difficult literary device. One was the eccentric Pierre de St. Louis, a Carmelite, whose book is dated 1672, and the other an Hungarian priest, who gave his contribution to the public in a work published as recently as 1869.

Luc. i. 28.
Ave, Maria, plena gratia; Dominus tecum.


Pierre de St. Louis, Carmelite, 1672.

Nigra sum. At Janua Coeli demum aperta.
Amica pia et Rosa grata, Lumenve Mundi.
Gemma Vitis in ea clara Domu pure nata.
Virgo clemens pia miranda, Eva mutata.
Regia summa Patrona, Clientem adjuva.
Virgo meum lumen, pia et sacrata Diana.
Ira placata rigidum mutas Evae nomen.
O Musa, jam ad te levia carmina pergunt.
Area mea totiusve Mundi ampla Regina.
Mater Carmeli. In eo, pia, munda, augusta.
Magna diu semper, Carmeli o Janua Tuta.
In Te valida via, magna sperat cor meum.
Amate prodigium naturas sine macula.
Semper inviolatam, argute canam. Audi.
Gemma tuis pie cara, in Domu Lauretana,
Jam tum via miranda per angelos vecta
Permagna Domus aurea in alta emicuit.
Vera, Alma Domus Agri Piceni tuta mane.
Amica ad te unam, jam Peregrinus volat.
Tu Dia, quam Pia, ore angeli arcanum sume.
Sanctuarium a Dei mei Angelo paratum.
Eia, Pia, Caram Mundo genitura salutem.
Ea pia, edita Regula omnium sanctarum.
Virgo casta Diana Emmanuelem rapuit.
Alma Porta jam antea Decus Virgineum.
Summa Diva ac Virgo plane intemerata.
Tam magna Deipara, una te jure colimus.
Via mea, Paradisi gratum Lumen, te cano
Intus a gaudio camera impleatur. Amen.
Mater cujus amaritudo ei plane magna
Elucens Virgo, tu jam pia Mater amanda.
In Amanda vivam ego. Petrus Carmelita
Mea Virago Lauretana est prima mundi.
Mira simul et pia, erga Numen advocata.
O Luna magnum a Dei pietate sacrarium.
O Unica sanave Margarita, Dei templum.
Summa Regina Poli, tute ac jure amanda.
Tu Regia, non Eva prima, sed Immaculata.
Sum Luna Picena amata, Virgo Mater Dei
Tu mea ardua ara, olim in Picenum gesta.
O veri Dei Munus, Palma, caritate magna.
Alma vere Integra, Pudica. Nos jam muta.
Due Regina et viam tutam sine malo para.
Num pia amata, et sacra Virgo de Lumine.
Eva intacta Deum jam paris angelorum.
Ita amata parens miraculo Deum genui.
Ardua sancta pia meum Genitorem alui.
Tu pia amica Mundo. Salve Regina Mater,
O augusta mire pia. Nunc Dei Mater alma.
Ipsa ter magna aut nimium decora. Vale.
Optima, cara Mater Numinis. Vale. Gaude.

This very eccentric Carmelite who framed the above fifty-one anagrams, and the first anagrammatic dialogue in Part I., some pages back, has been presented entire, and not tithed. The reasons of this special privilege are that he is rare to a degree, an “original” here and always, and the specimens above have been picked out, for the first time, from different parts of his work, for which, and for more about him, see the Bibliography.

Biblia anagrammatica (1904)

Mod’s Chosen

When you divide one integer by another, one of two things happens. Either the second number goes perfectly into the first or there’s a remainder:

15 / 5 = 3
18 / 5 = 3⅗

In the first case, there’s no remainder, that is, the remainder is 0. In the second case, there’s a remainder of 3. And all that gives you the basis for what’s called modular arithmetic. It returns the remainder when one number is divided by another:

15 mod 5 = 0
16 mod 5 = 1
17 mod 5 = 2
18 mod 5 = 3
19 mod 5 = 4
20 mod 5 = 0
21 mod 5 = 1
22 mod 5 = 2...

It looks simple but a lot of mathematics is built on it. I don’t know much of that maths, but I know one thing I like: the patterns you can get from modular arithmetic. Suppose you draw a square, then find a point and measure the distances from that point to all the vertices of the square. Then add the distances up, turn the result into an integer if necessary, and test whether the result is divisible by 2 or not. If it is divisible, colour the point in. If it isn’t, leave the point blank.

Then move on to another point and perform the same test. This is modular arithematic, because for each point you’re asking whether d mod 2 = 0. The result looks like this:

d mod 2 = 0

Here are more divisors:

d mod 3 = 0

d mod 4 = 0

d mod 5 = 0

d mod 6 = 0

d mod 7 = 0

d mod 8 = 0

d mod 9 = 0

d mod 10 = 0

d mod various = 0 (animated)

You can also use modular arithmetic to determine the colour of the points. For example, if d mod n = 0, the point is black; if d mod n = 1, the point is red; if d mod n = 2, the point is green; and so on.

d mod 3 = 0, 1, 2 (coloured)

d mod 4 = 0, 1, 2, 3 (coloured)

d mod 5 = 0, 1, 2, 3, 4 (coloured)

d mod 5 = 0, 1, 2, 3, 4 (animated and expanding)

Zequality Now

Here are the numbers one to eight in base 2:

1, 10, 11, 100, 101, 110, 111, 1000…

Now see what happens when you count the zeroes:

1, 10[1], 11, 10[2]0[3], 10[4]1, 110[5], 111, 10[6]0[7]0[8]...

In base 2, the numbers one to eight contain exactly eight zeroes, that is, zerocount(1..8,b=2) = 8. But it doesn’t work out so exactly in base 3:

1, 2, 10[1], 11, 12, 20[2], 21, 22, 10[3]0[4], 10[5]1, 10[6]2, 110[7], 111, 112, 120[8], 121, 122, 20[9]0[10], 20[11]1, 20[12]2, 210[13], 211, 212, 220[14], 221, 222, 10[15]0[16]0[17], 10[18]0[19]1, 10[20]0[21]2, 10[22]10[23], 10[24]11, 10[25]12, 10[26]20[27], 10[28]21, 10[29]22, 110[30]0[31], 110[32]1, 110[33]2, 1110[34], 1111, 1112, 1120[35], 1121, 1122, 120[36]0[37], 120[38]1, 120[39]2, 1210[40], 1211, 1212, 1220[41], 1221, 1222, 20[42]0[43]0[44], 20[45]0[46]1, 20[47]0[48]2, 20[49]10[50], 20[51]11, 20[52]12, 20[53]20[54], 20[55]21, 20[56]22, 210[57]0[58], 210[59]1, 210[60]2, 2110[61], 2111, 2112, 2120[62], 2121, 2122, 220[63]0[64], 220[65]1, 220[66]2, 2210[67], 2211, 2212, 2220[68], 2221, 2222, 10[69]0[70]0[71]0[72], 10[73]0[74]0[75]1, 10[76]0[77]0[78]2, 10[79]0[80]10[81], 10[82]0[83]11, 10[84]0[85]12, 10[86]0[87]20[88]...

In base 3, 10020 = 87 and zerocount(1..87,b=3) = 88. And what about base 4? zerocount(1..1068,b=4) = 1069 (n=100,230 in base 4). After that, zerocount(1..16022,b=5) = 16023 (n=1,003,043 in base 5) and zerocount(1..284704,b=6) = 284,705 (n=10,034,024 in base 6).

The numbers are getting bigger fast and it’s becoming increasingly impractible to count the zeroes individually. What you need is an algorithm that will take any given n and work out how many zeroes are required to write the numbers 1 to n. The simplest way to do this is to work out how many times 0 has appeared in each position of the number. The 1s position is easy: you simply divide the number by the base and discard the remainder. For example, in base 10, take the number 25. The 0 must have appeared in the 1s position twice, for 10 and 20, so zerocount(1..25) = 25 \ 10 = 2. In 2017, the 0 must have appeared in the 1s position 201 times = 2017 \ 10. And so on.

It gets a little trickier for the higher positions, the 10s, 100s, 1000s and so on, but the same basic principle applies. And so you can easily create an algorithm that takes a number, n, and produces zerocount(1..n) in a particular base. With this algorithm, you can quickly find zerocount(1..n) >= n in higher bases:

zerocount(1..1000,b=2) = 1,000 (n=8)*
zerocount(1..10020,b=3) = 10,021 (n=87)
zerocount(1..100230,b=4) = 100,231 (n=1,068)
zerocount(1..1003042,b=5) = 1,003,043 (n=16,022)
zerocount(1..10034024,b=6) = 10,034,025 (n=284,704)
zerocount(1..100405550,b=7) = 100,405,551 (n=5,834,024)
zerocount(1..1004500236,b=8) = 1,004,500,237 (n=135,430,302)
zerocount(1..10050705366,b=9) = 10,050,705,367 (n=3,511,116,537)
zerocount(1..100559404366,b=10) = 100,559,404,367
zerocount(1..1006083A68919,b=11) = 1,006,083,A68,919 (n=3,152,738,985,031)*
zerocount(1..10066AA1430568,b=12) = 10,066,AA1,430,569 (n=107,400,330,425,888)
zerocount(1..1007098A8719B81,b=13) = 100,709,8A8,719,B81 (n=3,950,024,143,546,664)*
zerocount(1..10077C39805D81C7,b=14) = 1,007,7C3,980,5D8,1C8 (n=155,996,847,068,247,395)
zerocount(1..10080B0034AA5D16D,b=15) = 10,080,B00,34A,A5D,171 (n=6,584,073,072,068,125,453)
zerocount(1..10088DBE29597A6C77,b=16) = 100,88D,BE2,959,7A6,C77 (n=295,764,262,988,176,583,799)*
zerocount(1..10090C5309AG72CBB3F,b=17) = 1,009,0C5,309,AG7,2CB,B3G (n=14,088,968,131,538,370,019,982)
zerocount(1..10099F39070FC73C1G73,b=18) = 10,099,F39,070,FC7,3C1,G75 (n=709,394,716,006,812,244,474,473)
zerocount(1..100A0DC1258614CA334EB,b=19) = 100,A0D,C12,586,14C,A33,4EC (n=37,644,984,315,968,494,382,106,708)
zerocount(1..100AAGDEEB536IBHE87006,b=20) = 1,00A,AGD,EEB,536,IBH,E87,008 (n=2,099,915,447,874,594,268,014,136,006)

And you can also easily find the zequal numbers, that is, the numbers n for which, in some base, zerocount(1..n) exactly equals n:

zerocount(1..1000,b=2) = 1,000 (n=8)
zerocount(1..1006083A68919,b=11) = 1,006,083,A68,919 (n=3,152,738,985,031)
zerocount(1..1007098A8719B81,b=13) = 100,709,8A8,719,B81 (n=3,950,024,143,546,664)
zerocount(1..10088DBE29597A6C77,b=16) = 100,88D,BE2,959,7A6,C77 (n=295,764,262,988,176,583,799)
zerocount(1..100CCJFFAD4MI409MI0798CJB3,b=24) = 10,0CC,JFF,AD4,MI4,09M,I07,98C,JB3 (n=32,038,681,563,209,056,709,427,351,442,469,835)
zerocount(1..100DDL38CIO4P9K0AJ7HK74EMI7L,b=26) = 1,00D,DL3,8CI,O4P,9K0,AJ7,HK7,4EM,I7L (n=160,182,333,966,853,031,081,693,091,544,779,177,187)
zerocount(1..100EEMHG6OE8EQKO0BF17LCCIA7GPE,b=28) = 100,EEM,HG6,OE8,EQK,O0B,F17,LCC,IA7,GPE (n=928,688,890,453,756,699,447,122,559,347,771,300,777,482)
zerocount(1..100F0K7MQO6K9R1S616IEEL2JRI73PF,b=29) = 1,00F,0K7,MQO,6K9,R1S,616,IEE,L2J,RI7,3PF (n=74,508,769,042,363,852,559,476,397,161,338,769,391,145,562)
zerocount(1..100G0LIL0OQLF2O0KIFTK1Q4DC24HL7BR,b=31) = 100,G0L,IL0,OQL,F2O,0KI,FTK,1Q4,DC2,4HL,7BR (n=529,428,987,529,739,460,369,842,168,744,635,422,842,585,510,266)
zerocount(1..100H0MUTQU3A0I5005WL2PD7T1ASW7IV7NE,b=33) = 10,0H0,MUT,QU3,A0I,500,5WL,2PD,7T1,ASW,7IV,7NE (n=4,262,649,311,868,962,034,947,877,223,846,561,239,424,294,726,563,632)
zerocount(1..100HHR387RQHK9OP6EDBJEUDAK35N7MN96LB,b=34) = 100,HHR,387,RQH,K9O,P6E,DBJ,EUD,AK3,5N7,MN9,6LB (n=399,903,937,958,473,433,782,862,763,628,747,974,628,490,691,628,136,485)
zerocount(1..100IISLI0CYX2893G9E8T4I7JHKTV41U0BKRHT,b=36) = 10,0II,SLI,0CY,X28,93G,9E8,T4I,7JH,KTV,41U,0BK,RHT (n=3,831,465,379,323,568,772,890,827,210,355,149,992,132,716,389,119,437,755,185)
zerocount(1..100LLX383BPWE[40]ZL0G1M[40]1OX[39]67KOPUD5C[40]RGQ5S6W9[36],b=42) = 10,0LL,X38,3BP,WE[40],ZL0,G1M,[40]1O,X[39]6,7KO,PUD,5C[40],RGQ,5S6,W9[36] (n=6,307,330,799,917,244,669,565,360,008,241,590,852,337,124,982,231,464,556,869,653,913,711,854)
zerocount(1..100MMYPJ[38]14KDV[37]OG[39]4[42]X75BE[39][39]4[43]CK[39]K36H[41]M[37][43]5HIWNJ,b=44) = 1,00M,MYP,J[38]1,4KD,V[37]O,G[39]4,[42]X7,5BE,[39][39]4,[43]CK,[39]K3,6H[41],M[37][43],5HI,WNJ (n=90,257,901,046,284,988,692,468,444,260,851,559,856,553,889,199,511,017,124,021,440,877,333,751,943)
zerocount(1..100NN[36]3813[38][37]16F6MWV[41]UBNF5FQ48N0JRN[40]E76ZOHUNX2[42]3[43],b=46) = 100,NN[36],381,3[38][37],16F,6MW,V[41]U,BNF,5FQ,48N,0JR,N[40]E,76Z,OHU,NX2,[42]3[43] (n=1,411,636,908,622,223,745,851,790,772,948,051,467,006,489,552,352,013,745,000,752,115,904,961,213,172,605)
zerocount(1..100O0WBZO9PU6O29TM8Y0QE3I[37][39]A7E4YN[44][42]70[44]I[46]Z[45][37]Q2WYI6,b=47) = 1,00O,0WB,ZO9,PU6,O29,TM8,Y0Q,E3I,[37][39]A,7E4,YN[44],[42]70,[44]I[46],Z[45][37],Q2W,YI6 (n=182,304,598,281,321,725,937,412,348,242,305,189,665,300,088,639,063,301,010,710,450,793,661,266,208,306,996)
zerocount(1..100PP[39]37[49]NIYMN[43]YFE[44]TDTJ00EAEIP0BIDFAK[46][36]V6V[45]M[42]1M[46]SSZ[40],b=50) = 1,00P,P[39]3,7[49]N,IYM,N[43]Y,FE[44],TDT,J00,EAE,IP0,BID,FAK,[46][36]V,6V[45],M[42]1,M[46]S,SZ[40] (n=444,179,859,561,011,965,929,496,863,186,893,220,413,478,345,535,397,637,990,204,496,296,663,272,376,585,291,071,790)
zerocount(1..100Q0Y[46][44]K[49]CKG[45]A[47]Z[43]SPZKGVRN[37]2[41]ZPP[36]I[49][37]EZ[38]C[44]E[46]00CG[38][40][48]ROV,b=51) = 10,0Q0,Y[46][44],K[49]C,KG[45],A[47]Z,[43]SP,ZKG,VRN,[37]2[41],ZPP,[36]I[49],[37]EZ,[38]C[44],E[46]0,0CG,[38][40][48],ROV (n=62,191,970,278,446,971,531,566,522,791,454,395,351,613,891,150,548,291,266,262,575,754,206,359,828,753,062,692,619,547)
zerocount(1..100QQ[40]TL[39]ZA[49][41]J[41]7Q[46]4[41]66A1E6QHHTM9[44]8Z892FRUL6V[46]1[38][41]C[40][45]KB[39],b=52) = 100,QQ[40],TL[39],ZA[49],41]J[41],7Q[46],4[41]6,6A1,E6Q,HHT,M9[44],8Z8,92F,RUL,6V[46],1[38][41],C[40][45],KB[39] (n=8,876,854,501,927,007,077,802,489,292,131,402,136,556,544,697,945,824,257,389,527,114,587,644,068,732,794,430,403,381,731)
zerocount(1..100S0[37]V[53]Y6G[51]5J[42][38]X[40]XO[38]NSZ[42]XUD[47]1XVKS[52]R[39]JAHH[49][39][50][54]5PBU[42]H3[45][46]DEJ,b=55) = 100,S0[37],V[53]Y,6G[51],5J[42],[38]X[40],XO[38],NSZ,[42]XU,D[47]1,XVK,S[52]R,[39]JA,HH[49],[39][50][54],5PB,U[42]H,3[45][46],DEJ (n=28,865,808,580,366,629,824,612,818,017,012,809,163,332,327,132,687,722,294,521,718,120,736,868,268,650,080,765,802,786,141,387,114)

Anne’s Hans’

Anne Cresacre by Hans Holbein

Anne Cresacre by Hans Holbein (c. 1527)

Prince, n’enquerez de sepmaine
Où elles sont, ne de cest an,
Que ce refrain ne vous remaine:
Mais où sont les neiges d’antan!

Ballade des Dames du temps jadis, François Villon (1431-c.1489)

Oh My Guardian #5

‘We’re stepping out of a binary’ – celebrating the art of marginalized LGBT Muslims

[…] The show features artwork themed around issues of Islamophobia, racism and homophobia to “highlight the struggles common among contemporary Muslim queer, trans and gender non-conforming communities,” said co-curator and activist Yas Ahmed. — ‘We’re stepping out of a binary’, The Guardian, 22/i/2018.

Elsewhere other-accessible:

Oh My Guardian #1
Oh My Guardian #2
Oh My Guardian #3
Oh My Guardian #4
Reds under the Thread

Nice Noise

Pre-previously on Overlord-in-terms-of-the-Über-Feral, I looked at how Tolkien used the word “noise” and concluded that he didn’t use it well:

He heard behind his head a creaking and scraping sound. […] There was a shriek and the light vanished. In the dark there was a snarling noise. – “Fog on the Barrowdowns”, Book One, VIII

Now I want to look at a much better writer: Ian Fleming. At first glance, he might seem to be using “noise” badly too in this bit of Live and Let Die (1954):

At about the time he [a treasure-seeking fisherman] should have reached the island the whole village of Shark Bay was awakened by the most horrible drumming noise. It seemed to come from inside the island. It was recognized as the beating of Voodoo drums. It started softly and rose slowly to a thunderous crescendo. Then it died down again and stopped. It lasted about five minutes. – ch. 16, “The Jamaica Version”

Should “drumming noise” not simply have been “drumming”? Well, no: Fleming got it right. The phrase “X noise” or “noise of X” should be used either when a noise resembles X but isn’t X or when there’s some doubt about whether it is X. In the extract above, Fleming’s choice of words captures what must have gone on in the minds of the observers, or rather the auditors: “What is that horrible noise from the island? It sounds like drums. Wait, it is drums. But how on earth could etc.” This is confirmed by what Fleming writes next: “It seemed to come… It was recognized as…”

And once the noise has been recognized, it can be described without qualification. This bit comes later in the chapter:

Strangways described his horror when, an hour after they had left to swim across the three hundred yards of water, the terrible drumming had started up somewhere inside the cliffs of the island.

In the previous chapter, there’s a use of “noise” that I’m not so sure about:

After a quarter of an hour’s meticulous work there was a slight cracking noise and the pane came away attached to the putty knob in his hand. – ch. 15, “Midnight Among the Worms”

Would “slight cracking” have been better? It’s not as clear-cut as “drumming noise”, but I think Fleming got it right again. “Cracking” is ambiguous, because it could have meant that the glass cracked physically but not audibly. Fleming was writing considerately, leaving his readers in no doubt about what he meant.

Now try this from Evelyn Waugh’s Put Out More Flags (1942), as Basil Seal watches one of his girlfriends panicked by an air-raid:

But Poppet was gone, helter-skelter, downstairs, making little moaning noises as she went.

Waugh was an even better writer than Fleming, but did he misuse “noises” there? I don’t think so. These alternatives don’t conjure the scene as effectively:

• But Poppet was gone, helter-skelter, downstairs, emitting little moans as she went.
• But Poppet was gone, helter-skelter, downstairs, uttering little moans as she went.

The noises Poppet was making weren’t real moans and the trailing phrase “making little moaning noises” mimics what Basil would have heard as Poppet fled downstairs.

I conclude that, unlike Tolkien, Fleming and Waugh were making nice noise:

nice, adj. and adv. … Particular, strict, or careful with regard to a specific point or thing. Obs. Fastidious in matters of literary taste or style. Obs.Oxford English Dictionary


“Describe yourself.” You can say it to people. And you can say it to numbers too. For example, here’s the number 3412 describing the positions of its own digits, starting at 1 and working upward:

3412 – the 1 is in the 3rd position, the 2 is in the 4th position, the 3 is in the 1st position, and the 4 is in the 2nd position.

In other words, the positions of the digits 1 to 4 of 3412 recreate its own digits:

3412 → (3,4,1,2) → 3412

The number 3412 describes itself – it’s autonomatic (from Greek auto, “self” + onoma, “name”). So are these numbers:


More precisely, they’re panautonomatic numbers, because they describe the positions of all their own digits (Greek pan or panto, “all”). But what if you use the positions of only, say, the 1s or the 3s in a number? In base ten, only one number describes itself like that: 1. But we’re not confined to base 10. In base 2, the positions of the 1s in 110 (= 6) are 1 and 10 (= 2). So 110 is monautonomatic in binary (Greek mono, “single”). 10 is also monautonomatic in binary, if the digit being described is 0: it’s in 2nd position or position 10 in binary. These numbers are monoautonomatic in binary too:

110100 = 52 (digit = 1)
10100101111 = 1327 (d=0)

In 110100, the 1s are in 1st, 2nd and 4th position, or positions 1, 10, 100 in binary. In 10100101111, the 0s are in 2nd, 4th, 5th and 7th position, or positions 10, 100, 101, 111 in binary. Here are more monautonomatic numbers in other bases:

21011 in base 4 = 581 (digit = 1)
11122122 in base 3 = 3392 (d=2)
131011 in base 5 = 5131 (d=1)
2101112 in base 4 = 9302 (d=1)
11122122102 in base 3 = 91595 (d=2)
13101112 in base 5 = 128282 (d=1)
210111221 in base 4 = 148841 (d=1)

For example, in 131011 the 1s are in 1st, 3rd, 5th and 6th position, or positions 1, 3, 10 and 11 in quinary. But these numbers run out quickly and the only monautonomatic number in bases 6 and higher is 1. However, there are infinitely long monoautonomatic integer sequences in all bases. For example, in binary this sequence at the Online Encyclopedia of Integer Sequences describes itself using the positions of its 1s:

A167502: 1, 10, 100, 111, 1000, 1001, 1010, 1110, 10001, 10010, 10100, 10110, 10111, 11000, 11010, 11110, 11111, 100010, 100100, 100110, 101001, 101011, 101100, 101110, 110000, 110001, 110010, 110011, 110100, 111000, 111001, 111011, 111101, 11111, …

In base 10, it looks like this:

A167500: 1, 2, 4, 7, 8, 9, 10, 14, 17, 18, 20, 22, 23, 24, 26, 30, 31, 34, 36, 38, 41, 43, 44, 46, 48, 49, 50, 51, 52, 56, 57, 59, 61, 62, 63, 64, 66, 67, 68, 69, 70, 71, 75, 77, 80, 83, 86, 87, 89, 91, 94, 95, 97, 99, 100, 101, 103, 104, 107, 109, 110, 111, 113, 114, 119, 120, 124, … (see A287515 for a similar sequence using 0s)

In any base, you can find some sequence of integers describing the positions of any of the digits in that base – for example, the 1s or the 7s. But the numbers in the sequence get very large very quickly in higher bases. For example, here are some opening sequences for the digits 0 to 9 in base 10:

3, 10, 1111110, … (d=0)
1, 3, 10, 200001, … (d=1)
3, 12, 100000002, … (d=2)
2, 3, 30, 10000000000000000000000003, … (d=3)
2, 4, 14, 1000000004, … (d=4)
2, 5, 105, … (d=5)
2, 6, 1006, … (d=6)
2, 7, 10007, … (d=7)
2, 8, 100008, … (d=8)
2, 9, 1000009, … (d=9)

In the sequence for d=0, the first 0 is in the 3rd position, the second 0 is in the 10th position, and the third 0 is in the 1111110th position. That’s why I’ve haven’t written the next number – it’s 1,111,100 digits long (= 1111110 – 10). But it’s theoretically possible to write the number. In the sequence for d=3, the next number is utterly impossible to write, because it’s 9,999,999,999,999,999,999,999,973 digits long (= 10000000000000000000000003 – 30). In the sequence for d=5, the next number is this:

1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000005 (100 digits long = 105 – 5).

And in fact there are an infinite number of such sequences for any digit in any base – except for d=1 in binary. Why is binary different? Because 1 is the only digit that can start a number in that base. With 0, you can invent a sequence starting like this:

111, 1110, 1111110, …

Or like this:

1111, 11111111110, …

Or like this:

11111, 1111111111111111111111111111110, …

And so on. But with 1, there’s no room for manoeuvre.